Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.7 Plane Curves and Parametric Equations - 10.7 Assess Your Understanding - Page 695: 1


amplitude: $3$ period:$\dfrac{\pi}{2}$

Work Step by Step

If a function has form $y=A\sin(\alpha x)$, then there $|A|$ stands for the amplitude and $T =\frac{2\pi}{\omega}$ stands for the period. Hence, here we have $|A|=|3|=3$ $\omega=4$, thus $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$
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