Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.6 Polar Equations of Conics - 10.6 Assess Your Understanding - Page 684: 4

Answer

$1,\lt1,\gt1 $

Work Step by Step

We know that for the eccentricity $e$, if $e=1$, the conic is a parabola $e\lt1$, the conic is an ellipse $e\gt1$, the conic is a hyperbola hence the answer is: $1,\lt1,\gt1 $
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