Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.6 Polar Equations of Conics - 10.6 Assess Your Understanding - Page 684: 12

Answer

Ellipse The directrix is parallel to the polar axis at a distance of 3 units above the pole.

Work Step by Step

We are given the equation in polar coordinates: $r=\dfrac{6}{8+2\sin\theta}$ Rewrite the equation: $r=\dfrac{\dfrac{6}{8}}{\dfrac{8+2\sin\theta}{8}}$ $r=\dfrac{\dfrac{3}{4}}{1+\dfrac{1}{4}\sin\theta}$ The equation is in the form: $r=\dfrac{ep}{1+e\sin\theta}$ Identify $e$ from the denominator, then $p$ from the numerator: $e=\dfrac{1}{4}$ $ep=\dfrac{3}{4}\Rightarrow \dfrac{1}{4}p=\dfrac{3}{4}\Rightarrow p=3$ Because $e<1$, the conic is an ellipse. The directrix is parallel to the polar axis at a distance of 3 units above the pole.
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