Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.4 The Hyperbola - 10.4 Assess Your Understanding - Page 669: 1

Answer

$5\sqrt2$

Work Step by Step

The distance $d$ from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is given by the formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence, using the formula above gives $d=\sqrt{(-2-3)^2+(1-(-4))^2}\\ d=\sqrt{(-5)^2+5^2}\\ d=\sqrt{25+25}\\ d=\sqrt{50}\\ d=\sqrt{25(2)}\\ d=5\sqrt2$
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