Answer
$b=4$
Work Step by Step
We know that $b=\sqrt{c^2-a^2}=\sqrt{5^2-3^2}=\sqrt{16}=4.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 10 - Analytic Geometry - 10.4 The Hyperbola - 10.4 Assess Your Understanding - Page 669: 12
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