Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - Chapter Review - Review Exercises - Page 41: 12

Answer

$(x+1)^2+(y+2)^2=1^2$.

Work Step by Step

The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. Hence our equation: $(x+1)^2+(y+2)^2=1^2$.
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