# Chapter 1 - Graphs - Chapter Review - Review Exercises - Page 41: 11

$(x+2)^2+(y-3)^2=4^2$.

#### Work Step by Step

The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. Hence our equation: $(x+2)^2+(y-3)^2=4^2$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.