## Precalculus (10th Edition)

$2$ is the $x$-intercept. $-3$ is the $y$-intercept. Refer to the graph below.
At the $x$-intercept we know that the point's y-coordinate will be $y=0$. Therefore we have to plug in $y=0$ to the equation in order to find the x-coordinate too. $3x-2y=6$ $3x-2(0)=6$ $3x=6$ $x=2$ $2$ is the $x$-intercept so $(2, 0)$ is on the line. At the $y$-intercept we know that the point's x-coordinate will be $x=0$. Therefore we have to plug in $x=0$ to the equation in order to find the x-coordinate too. $3x-2y=6$ $3(0)-2y=6$ $-2y=6$ $y=-3$ $-3$ is the $y$-intercept so $(0, -3)$ is on the line. Plot the two points then connect them using a line. Refer to the graph above.