Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.2 Graphs of Equations in Two Variables; Intercepts; Symmetry - 1.2 Assess Your Understanding - Page 17: 23

Answer

$x$-intercepts: $-1, 1$ $y$-intercept: $-1$ Refer to the graph below.

Work Step by Step

To find the $x$-intercept/s, set $y = 0$ then solve for the equation to obtain: \begin{align*} x^2 - 1 &= 0\\ x^2&=1\\ \sqrt{x^2}&=\pm\sqrt1\\ x&=\pm1 \end{align*} The $x$-intercepts are $\pm1$. To find the $y$-intercept/s, set $x = 0$ then solve the equation to obtain: \begin{align*} y &= (0)^2 - 1\\ y&=-1 \end{align*} The $y$-intercept is $- 1$. Create a table of values by assigning values to $x$, then solve for the corresponding value of $y$ for each $x$ to obtain: \begin{array}{ccc} &x &y &\text{point}\\ &-2 &3 &(-2, 3)\\ &-1 &0 &(-1, 0)\\ &0 &-1 &(0, -1)\\ &1 &0 &(1, 0)\\ &2 &3 &(2, 3) \end{array} Plot the points and connect them using a smooth curve. Refer to the graph above.
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