## Precalculus (10th Edition)

Only $(0, 0)$ is on the graph.
Plug in each $x$-coordinate into the given equation and see if the resulting $y$-value matches with the $y$-coordinate of the given point. If it does, then the point is on the graph of the given equation. $x=0$: $0^4-\sqrt{0}=0-0=0$. Thus, $(0, 0)$ is on the graph. $x=1$: $1^4-\sqrt{1}=1-1=0$. Thus, $(1, 1)$ is not on the graph. $x=2$: $2^4-\sqrt{2}=16-1.4=14.6$. Thus, $(2, 4)$ is not on the graph. So out of these points, only $(0, 0)$ is on the graph.