Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.1 The Distance and Midpoint Formulas - 1.1 Assess Your Understanding - Page 7: 30

Answer

$|a|\sqrt 2$ units

Work Step by Step

Use the formula $d(P_1,P_2)=\sqrt {(x_2-x_1)^2+(y_2-y_1)^2}$: $d((a,a),(0,0)) \\=\sqrt {(0-a)^2+(0-a)^2} \\=\sqrt {a^2+a^2} \\=\sqrt {2a^2} \\=|a|\sqrt 2$
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