Answer
\begin{align*}
&(a) \textbf{ Quadrant II}\\
&(b) \textbf{ X-axis}\\
&(c) \textbf{ Quadrant III}\\
&(d) \textbf{ Quadrant I}\\
&(e) \textbf{ Y-axis}\\
&(f) \textbf{ Quadrant IV}
\end{align*}
Work Step by Step
Commonly, most teach that there are only 4 different locations on an $xy$-plane when there are really 6 different locations (the 4 quadrants along with the 2 axes). So, to determine where a point is on an $xy$-plane, you have to look at all 4 sections to see where on the plane the point will be located (especially when plotted). In this case, this graph can help show where and how everything can be found.
This is how to determine a point on the 4 quadrants:
\begin{matrix}
& x-\text{coordinate} & y-\text{coordinate} & \text{Point}\\
\text{Quadrant: I}& + & + & (+,+)\\
\text{Quadrant: II} & - & + & (-,+)\\
\text{Quadrant: III} & - & - & (-,-)\\
\text{Quadrant: IV} & + & - & (+,-)\\\\
\end{matrix}
Since the $x$ and $y$ can be either a positive or negative number, this is how to determine a point on the 2 axes:
\begin{matrix}
& \text{Location} \\
(0,x) & x-\text{axis} \\
(y,0) & y-\text{axis}\\
\end{matrix}
With that being said, let's determine how the following points are based on the format shown.
a. Point $(-3,2)$
This point's $x$-coordinate, $-3$, is negative while its $y$-coordinate, $2$, is positive. So, if this point is (negative, positive), then that means that this point would be found in Quadrant II.
b. Point $(6,0)$
This point's $x$-coordinate, $6$, is positive while its $y$-coordinate, $0$, is well, $0$. So, if this point is (positive, 0), then that means that this point would be found on the $x$-axis.
c. Point $(-2,-2)$
This point's $x$-coordinate, $-2$, is negative while its $y$-coordinate, $-2$, is also negative. So, if this point is (negative, negative), then that means that this point would be found in Quadrant III.
d. Point $(6,5)$
This point's $x$-coordinate, $6$, is positive while its $y$-coordinate, $5$, is also positive. So, if this point is (positive, positive), then that means that this point would be found in Quadrant I.
e. Point $(0,-3)$
This point's $x$-coordinate, $0$, is well, $0$ while its $y$-coordinate, $-3$, is negative. So, if this point is (0, negative), then that means that this point would be found on the $y$-axis.
f. Point $(6,-3)$
This point's $x$-coordinate, $6$, is positive while its $y$-coordinate, $-3$, is negative. So, if this point is (positive, negative), then that means that this point would be found in Quadrant IV.
