Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A29: 2

Answer

$x^{4}-16$

Work Step by Step

This is a difference of squares, $(A-B)(A+B)=A^{2}-B^{2}$. $(x^{2}-4)(x^{2}+4)=(x^{2})^{2}-4^{2}=x^{4}-16$ Note: FOIL can also be used, $(x^{2}-4)(x^{2}+4)\\ =x^{2}\cdot x^{2}+x^{2}\cdot 4-4x^{2}-16\\ =x^{4}-16$
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