Answer
$x^{4}-16$
Work Step by Step
This is a difference of squares, $(A-B)(A+B)=A^{2}-B^{2}$.
$(x^{2}-4)(x^{2}+4)=(x^{2})^{2}-4^{2}=x^{4}-16$
Note: FOIL can also be used,
$(x^{2}-4)(x^{2}+4)\\
=x^{2}\cdot x^{2}+x^{2}\cdot 4-4x^{2}-16\\
=x^{4}-16$