Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A29: 12

Answer

$\text{(b) }$

Work Step by Step

$x^{2}$ is the square of $x$, while $64$ is the square of $8$. This is a difference of squares of $x$ and $8$. The given expression can be written as: $x^{2}-64=x^{2}-8^{2}$
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