Chapter 7 - Trigonometry and Periodic Functions - 7.2 The Sine and Cosine Functions - Exercises and Problems for Section 7.2 - Exercises and Problems - Page 277: 13

$(0,3.8)$

Since $360-270=90$, $-270^\circ$=$90^\circ$. It is known that the coordinate on the $x$-$y$ plane for an angle $\theta$ from the horizontal and a radius $r$ is $(rcos\theta,rsin\theta)$. Using $r=3.8$ and $\theta=90^\circ$ gives a point $$(3.8cos(90^\circ),3.8sin(90^\circ))=(0,3.8)$$