Answer
$(0,-3.8)$
Work Step by Step
It is known that the coordinate on the $x$-$y$ plane for an angle $\theta$ from the horizontal and a radius $r$ is $(rcos\theta,rsin\theta)$. Using $r=3.8$ and $\theta=-90^\circ$ gives a point $$(3.8cos(-90^\circ),3.8sin(-90^\circ))=(0,-3.8)$$