## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$x=\frac{1}{5},\:x=-\frac{1}{5}$$
Solving the equation for x, we find: $$\frac{5}{x^2}=125 \\ 5=125x^2 \\ x=\frac{1}{5},\:x=-\frac{1}{5}$$