## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$$3a^7b^{10}$$
Simplifying the expression using the rules of exponents, we find: $$\frac{3b^6a^{10-3}}{b^{-4}} \\ 3a^7b^{6-\left(-4\right)} \\ 3a^7b^{10}$$