Answer
a) 25 mg
b) $15\%$
c) 4.92 mg
d) About 20 hours.
Work Step by Step
Given
$$A(t) =25\cdot (0.85)^{t} $$
A) The initial dose is $25$ mg.
B)The percentage of the drug leaving the body is $r= 1-0.85 = 0.15= 15\%$.
C)
\begin{equation}
\begin{aligned}
y&=25\cdot (0.85)^{10}\\
&= 4.92\\
\end{aligned}
\end{equation}
D) Use
$t=\log_{0.85}(A(t)/25)$
\begin{equation}
\begin{aligned}
t&=\log_{0.85}(A(t)/25)\\
&= \log_{0.85}(1/25)\\
&= 19.80
\end{aligned}
\end{equation} About 20 hours.