Chapter 3 - Quadratic Functions - Review Exercises and Problems for Chapter Three - Page 130: 21

i) Vertex: $(3 / 4,-2 / 3)$ ii) Axis of symmetry: $x= 3/4$ iii) $x= 0$, $y$-intercept: $y=2(3 / 4)^2-2 / 3=11 / 24$ iv) Since the coefficient $a$ is positive the curve is concave up.

Give $y=2(x-3 / 4)^2-2 / 3$ i) Vertex: $(3 / 4,-2 / 3)$ ii) Axis of symmetry: $x= 3/4$ iii) $x= 0$, $y$-intercept: $y=2(3 / 4)^2-2 / 3=11 / 24$ iv) Since the coefficient $a$ is positive the curve is concave up.