Answer
$ y=\frac{7}{9}\cdot(x-3)^2-5$
Work Step by Step
The vertex form of the parabola is $y=a(x-3)^2-5$ and if $x=0, y=2$, so
$$
\begin{aligned}
a(0-3)^2-5 & =2 \\
9 a & =7 \\
a & =\frac{7}{9}
\end{aligned}
$$
Hence $$ y=\frac{7}{9}\cdot(x-3)^2-5.$$
