Answer
$$t=-\frac{-2+\sqrt{31}}{3},\:t=\frac{2+\sqrt{31}}{3}$$
Work Step by Step
Using the quadratic formula, we find:
$$t=\frac{-4+\sqrt{4^2-4\left(-3\right)9}}{2\left(-3\right)} \\ t=-\frac{-2+\sqrt{31}}{3},\:t=\frac{2+\sqrt{31}}{3}$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Skill Refresher - Page 127: S8
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