Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Skill Refresher - Page 127: S5



Work Step by Step

Completing the square, we find: $$ r^2-6r+8+\left(-3\right)^2-\left(-3\right)^2 \\ \left(r-3\right)^2+8-\left(-3\right)^2 \\ \left(r-3\right)^2-1$$ Setting this equal to zero: $$ \left(r-3\right)^2=1 \\ r=4,\:r=2$$
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