Answer
$n<0$.
Work Step by Step
$$
\begin{aligned}
-3(n-4) & >12 \\
\frac{-3(n-4)}{-3} & <\frac{12}{-3} \\
n-4 & <-4 \\
n-4+4 & <-4+4 \\
n & <0 .
\end{aligned}
$$
The solution of the inequality is $n<0$.
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