Answer
$-6 \leq x \leq 6$.
Work Step by Step
We have $36-x^2 \geq 0$ when $x^2\leq 36$, so $-6 \leq x \leq 6$.
This because both $36-(-6)^2= 0$ and $36-(6)^2= 0$ satisfy the inequality.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 2 - Functions - 2.2 Domain and Range - Exercises and Problems for Section 2.2 - Skill Refresher - Page 82: S10
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