## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$-x+3+\frac{2}{x^2}$
Using the fact that $$(\frac{a}{b})^n=\frac{a^n}{b^n}$$ $(\frac{1}{x})^2=\frac{1^2}{x^2}=\frac{1}{x^2}$. The expression is simplified to $3+\frac{2}{x^2}-x$, or $-x+3+\frac{2}{x^2}$.