Answer
$
\frac{g(t+h)-g(t)}{h}=2
$
Work Step by Step
Since $g(t+h)=2(t+h)-1$ we have
$$
\frac{g(t+h)-g(t)}{h}=\frac{2(t+h)-1-(2 t-1)}{h}=\frac{2 t+2 h-1-2 t+1}{h}=\frac{2 h}{h}=2
$$
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