Answer
a) 4
b) $4+4h+h^2$
c) $4h+h^2$
d) $4+h$
Work Step by Step
(a) $f(2)=2^2=4$
(b) $f(2+h)=(2+h)^2=4+4 h+h^2$.
(c) Using the answers to (a) and (b), we have $f(2+h)-f(2)=4+4 h+h^2-4=4 h+h^2$.
d) $$
\frac{f(2+h)-f(2)}{h}=\frac{4 h+ h^2}{h}= 4+h
$$