Answer
a) In the year $2004$, a member's salary was $\$ 158,100$ .
b) A member's salary was $\$ 169,300$ in $2008$.
Work Step by Step
(a) Table 2.2 in the text shows that $f(12)=158.1$. Here, $t=12$ corresponds to the year $1992+12=2004$, therefore, a member's salary was $\$ 158,1$ in the year $2004$.
b) Solving $f(t)=169.3$ means finding the year in which a member's salary was $\$ 169,300$; it is $t=16$.This means that a member's salary was $\$ 169,3$ in $1992+16=2008$.