Answer
$$0$$
Work Step by Step
Recall: $\vec{i}\cdot \vec{j}=\vec{j}\cdot \vec{k}=\vec{k}\cdot \vec{i}=0$
We simplify:
$(2\vec{i} \cdot 5 \vec{j})(\vec{i}+\vec{j}+\vec{k})=(0) (\vec{i}+\vec{j}+\vec{k}) \\ =0$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 12 - Vectors and Matrices - Review Exercises and Problems for Chapter Twelve - Page 532: 16
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