Answer
$$\hat{i}+0\hat{j}+\hat{k}$$
Work Step by Step
Subtracting the final point from the initial point of the vector for each component, we find:
$$(2-1)\hat{i}+(4-4)\hat{j}+(1-0)\hat{k} \\ \hat{i}+0\hat{j}+\hat{k}$$
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