Answer
$$ \hat{i}+4\hat{j}+0\hat{k}$$
Work Step by Step
Subtracting the final point from the initial point of the vector for each component, we find:
$$(1-0)\hat{i}+(4-0)\hat{j}+(0-0)\hat{k} \\ \hat{i}+4\hat{j}+0\hat{k}$$
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