Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Practice: 2

Answer

$A=48\frac{4}{5}$ sq yd

Work Step by Step

$A=\frac{(a+b)}{2}h$ $A=\frac{(11+5)}{2}\times6.1$ $A=\frac{16}{2}\times6\frac{1}{10}$ $A=\frac{8}{1}\times\frac{61}{10}$ $A=\frac{4}{1}\times\frac{61}{5}$ $A=\frac{244}{5}$ $A=48\frac{4}{5}$ sq yd
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