Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Practice - Page 624: 1


$A=49\frac{1}{2}$ sq in.

Work Step by Step

$A=\frac{1}{2}bh$, $A=\frac{1}{2}\times8\frac{1}{4}\times12$ $A=\frac{1}{2}\times\frac{33}{4}\times\frac{12}{1}$ $A=\frac{33}{8}\times\frac{12}{1}$ $A=\frac{33}{2}\times\frac{3}{1}$ $A=\frac{99}{2}$ $A=49\frac{1}{2}$ sq in.
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