## Prealgebra (7th Edition)

Circumference = 16$\pi$ mi The approximation of the circumference = 50.24 $mi^{2}$
Circumference = 2 $\times$ $\pi$ $\times$ radius = 2 $\times$ $\pi$ $\times$ r Circumference = 2 $\times$ $\pi$ $\times$ 8 = 16$\pi$ mi The approximation of the circumference = 2 $\times$ (3.14) $\times$ 8 = 50.24 $mi^{2}$