## Prealgebra (7th Edition)

Circumference = 5$\pi$ in. The approximation of the circumference = 15.7 $in.^{2}$
Circumference = 2 $\times$ $\pi$ $\times$ radius = 2 $\times$ $\pi$ $\times$ r C = 2 $\times$ $\pi$ $\times$ 2.5 = 5$\pi$ The approximation of the circumference = 2 $\times$ (3.14) $\times$ 2.5 = 15.7 $in.^{2}$