## Prealgebra (7th Edition)

7 problems in 6 minutes How many problems in minute ? $\frac{7}{6}$ problems How many problems in 30 minutes? $\frac{7}{6}$ $\times$30= =$\frac{7\times30}{6}$=$\frac{7\times5\times6}{6}$=35 problems in 30 minutes