Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 7 - Cumulative Review - Page 530: 24

Answer

a. $\frac{17}{5}$ b. $\frac{44}{7}$

Work Step by Step

a. 3$\frac{2}{5}$=3+$\frac{2}{5}$= write 3 like $\frac{15}{5}$ =$\frac{15}{5}$+$\frac{2}{5}$=$\frac{17}{5}$ b. 6$\frac{2}{7}$=6+$\frac{2}{7}$= write 6 like $\frac{42}{7}$ =$\frac{42}{7}$+$\frac{2}{7}$=$\frac{44}{7}$
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