Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.4 - Square Roots and the Pythagorean Theorem - Exercise Set - Page 445: 47

Answer

1.732

Work Step by Step

$x^2 + 1^2 = 2^2$ $x^2 + 1 = 4$ $x^2 = 3$ $x = 1.732$
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