# Chapter 6 - Section 6.4 - Square Roots and the Pythagorean Theorem - Exercise Set - Page 445: 33

$\sqrt 2788$ $\approx$ 52.802

#### Work Step by Step

$a^{2}$ +$b^{2}$ =$c^{2}$ Let a=22 cm and b=48cm $22^{2}$ +$48^{2}$ =$c^{2}$ 484+2304 =$c^{2}$ 2788 =$c^{2}$ c=$\sqrt 2788$ c$\approx$52.802 The hypotenuse is exactly $\sqrt 2788$ and approximately 52.802

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