Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.4 - Square Roots and the Pythagorean Theorem - Exercise Set: 5

Answer

$\frac{1}{9}$

Work Step by Step

$\sqrt {\frac{1}{81}}=\frac{1}{9}$ because $(\frac{1}{9})^2=\frac{1}{81}$
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