Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.4 - Square Roots and the Pythagorean Theorem - Exercise Set - Page 444: 18


$5\leq\sqrt {27}\leq6$ $\sqrt {27}=5.196$

Work Step by Step

$5\times5=25$ $6\times6=36$ $5\leq\sqrt {27}\leq6$ Using a calculator, $\sqrt {27}=5.196\checkmark$
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