## Prealgebra (7th Edition)

The solution is -$\frac{7}{10}$
$\frac{2}{5}$ + y= -$\frac{3}{10}$ $\frac{2}{5}$+y -$\frac{2}{5}$=- $\frac{3}{10}$-$\frac{2}{5}$ Subtract $\frac{2}{5}$ to both sides $y=-\frac{3}{10}$-$\frac{4}{10}$ LCD of the denominators 10 and 5 is 10 $y=-\frac{3}{10}$-$\frac{2}{5}$ $y=-\frac{3}{10}$-$\frac{4}{10}$ $y=\frac{-3-4}{10}$ $y= -\frac{7}{10}$ The solution is -$\frac{7}{10}$ Check Replace y with $\frac{-7}{10}$ $\frac{2}{5}$ +y=-$\frac{3}{10}$ $\frac{2}{5}$ -$\frac{7}{10}$=-$\frac{3}{10}$ $\frac{4}{10}$ -$\frac{7}{10}$=-$\frac{3}{10}$ -$\frac{3}{10}$=-$\frac{3}{10}$