## Prealgebra (7th Edition)

The solution is $\frac{4}{5}$
3x - $\frac{1}{5}$ - 2x = $\frac{1}{5}$+$\frac{2}{5}$ Simplify 3x - 2x - $\frac{1}{5}$ = $\frac{1+2}{5}$ x-$\frac{1}{5}$ = $\frac{3}{5}$ Add $\frac{1}{5}$ to both sides x-$\frac{1}{5}$ +$\frac{1}{5}$ = $\frac{3}{5}$ + $\frac{1}{5}$ x= $\frac{3+1}{5}$ x=$\frac{4}{5}$ The solution is $\frac{4}{5}$ Check Replace x with $\frac{4}{5}$ 3x- $\frac{1}{5}$ -2x= $\frac{1}{5}$+$\frac{2}{5}$ 3$\times$ $\frac{4}{5}$ - $\frac{1}{5}$ - 2$\times$$\frac{4}{5}$= $\frac{1}{5}$+$\frac{2}{5}$ $\frac{3\times4}{5}$ - $\frac{1}{5}$ - $\frac{2\times4}{5}$= $\frac{1+2}{5}$ $\frac{12}{5}$ - $\frac{1}{5}$ - $\frac{8}{5}$= $\frac{3}{5}$ $\frac{12-1-8}{5}$ = $\frac{3}{5}$ $\frac{3}{5}$ = $\frac{3}{5}$