Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Integrated Review - Summary on Fractions and Operations on Fractions - Page 278: 46

Answer

$\frac{25y + 12}{50}$

Work Step by Step

$\frac{3y}{10} + \frac{y}{5} + \frac{6}{25} = \frac{15y}{50} + \frac{10y}{50} + \frac{12}{50} = \frac{25y + 12}{50}$
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