Answer
$-\frac{7}{48z}$
Work Step by Step
$-\frac{7z}{8} \div 6z^{2} = \frac{-7z}{8} \div \frac{6z^{2}}{1} = \frac{-7z}{8} \times \frac{1}{6z^{2}} = \frac{-7z}{48z^{2}} = \frac{-7}{48z} = -\frac{7}{48z}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 4 - Section 4.5 - Integrated Review - Summary on Fractions and Operations on Fractions - Page 278: 41
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