Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.4 - Introduction to Factoring Polynomials - Exercise Set - Page 723: 29

Answer

$12a^5(1-3a)$

Work Step by Step

$\begin{aligned}12a^5-36a^6&=12\cdot a^5-3\cdot 12\cdot a^5\cdot a\\&=12a^5(1-3a)\end{aligned}$
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