## Prealgebra (7th Edition)

$12a^4b^5\ m^2$
The area of a triangle is $\frac{1}{2}bh$. $\frac{1}{2}(6a^3b^4)(4ab)=(\frac{1}{2})(6)(4)(a^{(3+1)})(b^{(4+1)})=12a^4b^5$