Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Multiplication Properties of Exponents - Exercise Set: 41

Answer

$12a^4b^5\ m^2$

Work Step by Step

The area of a triangle is $\frac{1}{2}bh$. $\frac{1}{2}(6a^3b^4)(4ab)=(\frac{1}{2})(6)(4)(a^{(3+1)})(b^{(4+1)})=12a^4b^5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.