Answer
$x^{56}y^{32}$
Work Step by Step
$(x^{7}y^4)^8=x^{(7\times8)}y^{(4\times8)}=x^{56}y^{32}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 10 - Section 10.2 - Multiplication Properties of Exponents - Exercise Set - Page 711: 26
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