## Prealgebra (7th Edition)

$-11y^2-y+\frac{3}{4}$
Subtract $9y^2$ from $-20y^2$ to get $-11y^2$ Subtract y. So far you have $-11y^2-y$ Add $\frac{1}{2}$ and $\frac{1}{4}$. The $-\frac{1}{4}$ becomes positive because the two negative signs cancel out. Result: $-11y^2-y+\frac{3}{4}$