Answer
$-11y^2-y+\frac{3}{4}$
Work Step by Step
Subtract $9y^2$ from $-20y^2$ to get $-11y^2$
Subtract y. So far you have $-11y^2-y$
Add $\frac{1}{2}$ and $\frac{1}{4}$. The $-\frac{1}{4}$ becomes positive because the two negative signs cancel out.
Result: $-11y^2-y+\frac{3}{4}$
